YES Termination Proof

Termination Proof

by ttt2 (version ttt2 1.15)

Input

The rewrite relation of the following TRS is considered.

a(a(x0)) b(a(b(x0)))
b(b(x0)) a(c(b(x0)))
c(c(x0)) c(b(a(x0)))
a(b(x0)) b(a(x0))
b(c(x0)) c(x0)

Proof

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a#(a(x0)) b#(x0)
a#(a(x0)) a#(b(x0))
a#(a(x0)) b#(a(b(x0)))
b#(b(x0)) c#(b(x0))
b#(b(x0)) a#(c(b(x0)))
c#(c(x0)) a#(x0)
c#(c(x0)) b#(a(x0))
c#(c(x0)) c#(b(a(x0)))
a#(b(x0)) a#(x0)
a#(b(x0)) b#(a(x0))

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.