YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
b(a(b(x0))) |
→ |
a(b(a(x0))) |
b(b(a(x0))) |
→ |
b(b(b(x0))) |
c(a(x0)) |
→ |
a(b(c(x0))) |
c(b(x0)) |
→ |
b(a(c(x0))) |
Proof
1 Rule Removal
Using the
linear polynomial interpretation over the naturals
[a(x1)] |
= |
1 ·
x1 + 1 |
[b(x1)] |
= |
1 ·
x1 + 1 |
[c(x1)] |
= |
8 ·
x1 + 14 |
the
rules
b(a(b(x0))) |
→ |
a(b(a(x0))) |
b(b(a(x0))) |
→ |
b(b(b(x0))) |
remain.
1.1 String Reversal
Since only unary symbols occur, one can reverse all terms and obtains the TRS
b(a(b(x0))) |
→ |
a(b(a(x0))) |
a(b(b(x0))) |
→ |
b(b(b(x0))) |
1.1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
b#(a(b(x0))) |
→ |
a#(x0) |
b#(a(b(x0))) |
→ |
b#(a(x0)) |
b#(a(b(x0))) |
→ |
a#(b(a(x0))) |
a#(b(b(x0))) |
→ |
b#(b(b(x0))) |
1.1.1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over the arctic semiring over the integers
[a#(x1)] |
= |
0 ·
x1 +
-∞
|
[a(x1)] |
= |
1 ·
x1 +
-∞
|
[b#(x1)] |
= |
0 ·
x1 +
-∞
|
[b(x1)] |
= |
1 ·
x1 +
-∞
|
together with the usable
rules
b(a(b(x0))) |
→ |
a(b(a(x0))) |
a(b(b(x0))) |
→ |
b(b(b(x0))) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pairs
b#(a(b(x0))) |
→ |
a#(b(a(x0))) |
a#(b(b(x0))) |
→ |
b#(b(b(x0))) |
remain.
1.1.1.1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1
over the arctic semiring over the integers
[a#(x1)] |
= |
·
x1 +
1 |
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
|
[a(x1)] |
= |
·
x1 +
|
[b#(x1)] |
= |
·
x1 +
0 |
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
|
[b(x1)] |
= |
·
x1 +
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
-∞
|
0 |
-∞
|
-∞
|
|
together with the usable
rules
b(a(b(x0))) |
→ |
a(b(a(x0))) |
a(b(b(x0))) |
→ |
b(b(b(x0))) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pair
b#(a(b(x0))) |
→ |
a#(b(a(x0))) |
remains.
1.1.1.1.1.1 Dependency Graph Processor
The dependency pairs are split into 0
components.