YES
0 QTRS
↳1 RootLabelingProof (⇔, 0 ms)
↳2 QTRS
↳3 DependencyPairsProof (⇔, 1 ms)
↳4 QDP
↳5 DependencyGraphProof (⇔, 0 ms)
↳6 TRUE
a(b(a(x))) → a(b(b(a(x))))
b(b(b(x))) → b(b(x))
a_{b_1}(b_{a_1}(a_{a_1}(x))) → a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(x))))
a_{b_1}(b_{a_1}(a_{b_1}(x))) → a_{b_1}(b_{b_1}(b_{a_1}(a_{b_1}(x))))
b_{b_1}(b_{b_1}(b_{a_1}(x))) → b_{b_1}(b_{a_1}(x))
b_{b_1}(b_{b_1}(b_{b_1}(x))) → b_{b_1}(b_{b_1}(x))
A_{B_1}(b_{a_1}(a_{a_1}(x))) → A_{B_1}(b_{b_1}(b_{a_1}(a_{a_1}(x))))
A_{B_1}(b_{a_1}(a_{a_1}(x))) → B_{B_1}(b_{a_1}(a_{a_1}(x)))
A_{B_1}(b_{a_1}(a_{b_1}(x))) → A_{B_1}(b_{b_1}(b_{a_1}(a_{b_1}(x))))
A_{B_1}(b_{a_1}(a_{b_1}(x))) → B_{B_1}(b_{a_1}(a_{b_1}(x)))
a_{b_1}(b_{a_1}(a_{a_1}(x))) → a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(x))))
a_{b_1}(b_{a_1}(a_{b_1}(x))) → a_{b_1}(b_{b_1}(b_{a_1}(a_{b_1}(x))))
b_{b_1}(b_{b_1}(b_{a_1}(x))) → b_{b_1}(b_{a_1}(x))
b_{b_1}(b_{b_1}(b_{b_1}(x))) → b_{b_1}(b_{b_1}(x))