YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Zantema_04/z106.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(a(x)) → b(b(b(x)))
b(x) → c(c(d(x)))
c(x) → d(d(d(x)))
b(c(x)) → c(b(x))
b(c(d(x))) → a(x)

Q is empty.

(1) QTRSRRRProof (EQUIVALENT transformation)

Used ordering:
Polynomial interpretation [POLO]:

POL(a(x1)) = 47 + x1   
POL(b(x1)) = 31 + x1   
POL(c(x1)) = 13 + x1   
POL(d(x1)) = 4 + x1   
With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:

a(a(x)) → b(b(b(x)))
b(x) → c(c(d(x)))
c(x) → d(d(d(x)))
b(c(d(x))) → a(x)


(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

b(c(x)) → c(b(x))

Q is empty.

(3) Overlay + Local Confluence (EQUIVALENT transformation)

The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.

(4) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

b(c(x)) → c(b(x))

The set Q consists of the following terms:

b(c(x0))

(5) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

B(c(x)) → B(x)

The TRS R consists of the following rules:

b(c(x)) → c(b(x))

The set Q consists of the following terms:

b(c(x0))

We have to consider all minimal (P,Q,R)-chains.

(7) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

B(c(x)) → B(x)

R is empty.
The set Q consists of the following terms:

b(c(x0))

We have to consider all minimal (P,Q,R)-chains.

(9) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

b(c(x0))

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

B(c(x)) → B(x)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • B(c(x)) → B(x)
    The graph contains the following edges 1 > 1

(12) YES