YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-563.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(b(x)) → x
a(c(x)) → c(c(b(a(x))))
b(c(x)) → a(b(x))

Q is empty.

(1) QTRS Reverse (EQUIVALENT transformation)

We applied the QTRS Reverse Processor [REVERSE].

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

b(a(x)) → x
c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))

Q is empty.

(3) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

C(a(x)) → B(c(c(x)))
C(a(x)) → C(c(x))
C(a(x)) → C(x)
C(b(x)) → B(a(x))

The TRS R consists of the following rules:

b(a(x)) → x
c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

C(a(x)) → C(x)
C(a(x)) → C(c(x))

The TRS R consists of the following rules:

b(a(x)) → x
c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


C(a(x)) → C(x)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation:
POL( C(x1) ) = 2x1

POL( c(x1) ) = x1 + 2

POL( a(x1) ) = x1 + 2

POL( b(x1) ) = max{0, x1 - 2}


The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))
b(a(x)) → x

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

C(a(x)) → C(c(x))

The TRS R consists of the following rules:

b(a(x)) → x
c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


C(a(x)) → C(c(x))
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO,RATPOLO]:

POL(C(x1)) = x1   
POL(a(x1)) = [1] + [4]x1   
POL(b(x1)) = [3/4] + [1/4]x1   
POL(c(x1)) = [4]x1   
The value of delta used in the strict ordering is 1.
The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))
b(a(x)) → x

(10) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

b(a(x)) → x
c(a(x)) → a(b(c(c(x))))
c(b(x)) → b(a(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(12) YES