YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-541.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(c(x)) → A(a(x))
A(c(x)) → A(x)

The TRS R consists of the following rules:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(c(x)) → A(x)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation:
POL( A(x1) ) = x1

POL( a(x1) ) = x1 + 2

POL( b(x1) ) = max{0, x1 - 2}

POL( c(x1) ) = x1 + 2


The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(c(x)) → A(a(x))

The TRS R consists of the following rules:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(c(x)) → A(a(x))
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO,RATPOLO]:

POL(A(x1)) = [4]x1   
POL(a(x1)) = [2]x1   
POL(b(x1)) = [2] + [1/2]x1   
POL(c(x1)) = [4] + [2]x1   
The value of delta used in the strict ordering is 16.
The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

(6) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

a(b(x)) → x
a(b(x)) → b(c(x))
a(c(x)) → c(b(a(a(x))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(8) YES