(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
a(a(b(x))) → b(b(c(a(a(a(x))))))
b(c(a(x))) → x
Q is empty.
(1) QTRS Reverse (EQUIVALENT transformation)
We applied the QTRS Reverse Processor [REVERSE].
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
b(a(a(x))) → a(a(a(c(b(b(x))))))
a(c(b(x))) → x
Q is empty.
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
B(a(a(x))) → A(a(a(c(b(b(x))))))
B(a(a(x))) → A(a(c(b(b(x)))))
B(a(a(x))) → A(c(b(b(x))))
B(a(a(x))) → B(b(x))
B(a(a(x))) → B(x)
The TRS R consists of the following rules:
b(a(a(x))) → a(a(a(c(b(b(x))))))
a(c(b(x))) → x
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 3 less nodes.
(6) Obligation:
Q DP problem:
The TRS P consists of the following rules:
B(a(a(x))) → B(x)
B(a(a(x))) → B(b(x))
The TRS R consists of the following rules:
b(a(a(x))) → a(a(a(c(b(b(x))))))
a(c(b(x))) → x
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(7) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04,JAR06].
The following pairs can be oriented strictly and are deleted.
B(a(a(x))) → B(x)
B(a(a(x))) → B(b(x))
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation:
POL( B(x1) ) = max{0, x1 - 1} |
POL( c(x1) ) = max{0, x1 - 2} |
The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:
b(a(a(x))) → a(a(a(c(b(b(x))))))
a(c(b(x))) → x
(8) Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:
b(a(a(x))) → a(a(a(c(b(b(x))))))
a(c(b(x))) → x
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(9) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(10) YES