YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-337.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → b(x)
a(a(b(x))) → a(b(a(a(c(x)))))
c(b(x)) → x

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(b(x))) → A(b(a(a(c(x)))))
A(a(b(x))) → A(a(c(x)))
A(a(b(x))) → A(c(x))
A(a(b(x))) → C(x)

The TRS R consists of the following rules:

a(x) → b(x)
a(a(b(x))) → a(b(a(a(c(x)))))
c(b(x)) → x

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(b(x))) → A(c(x))
A(a(b(x))) → A(a(c(x)))

The TRS R consists of the following rules:

a(x) → b(x)
a(a(b(x))) → a(b(a(a(c(x)))))
c(b(x)) → x

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(a(b(x))) → A(a(c(x)))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[-I,0A,0A]
·x1

POL(a(x1)) =
/1A\
|0A|
\0A/
+
/1A0A1A\
|0A-I0A|
\0A-I0A/
·x1

POL(b(x1)) =
/1A\
|0A|
\-I/
+
/-I0A1A\
|0A-I0A|
\0A-I0A/
·x1

POL(c(x1)) =
/0A\
|1A|
\0A/
+
/-I-I0A\
|0A0A1A|
\-I-I0A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

c(b(x)) → x
a(x) → b(x)
a(a(b(x))) → a(b(a(a(c(x)))))

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(b(x))) → A(c(x))

The TRS R consists of the following rules:

a(x) → b(x)
a(a(b(x))) → a(b(a(a(c(x)))))
c(b(x)) → x

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) UsableRulesProof (EQUIVALENT transformation)

We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(b(x))) → A(c(x))

The TRS R consists of the following rules:

c(b(x)) → x

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) MNOCProof (EQUIVALENT transformation)

We use the modular non-overlap check [LPAR04] to enlarge Q to all left-hand sides of R.

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(b(x))) → A(c(x))

The TRS R consists of the following rules:

c(b(x)) → x

The set Q consists of the following terms:

c(b(x0))

We have to consider all minimal (P,Q,R)-chains.

(11) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(a(b(x))) → A(c(x))
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation:
POL( A(x1) ) = max{0, 2x1 - 2}

POL( c(x1) ) = x1

POL( b(x1) ) = 2x1 + 2

POL( a(x1) ) = x1


The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

c(b(x)) → x

(12) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

c(b(x)) → x

The set Q consists of the following terms:

c(b(x0))

We have to consider all minimal (P,Q,R)-chains.

(13) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(14) YES