YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-265.srs

Termination w.r.t. Q of the given QTRS could be proven:

0 QTRS
↳1 DependencyPairsProof (⇔, 0 ms)
↳2 QDP
↳3 DependencyGraphProof (⇔, 0 ms)
↳4 QDP
↳5 QDPOrderProof (⇔, 112 ms)
↳6 QDP
↳7 DependencyGraphProof (⇔, 0 ms)
↳8 TRUE

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → x
a(b(x)) → c(x)
b(x) → x
c(c(x)) → b(b(a(a(c(x)))))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(x)) → C(x)
C(c(x)) → B(b(a(a(c(x)))))
C(c(x)) → B(a(a(c(x))))
C(c(x)) → A(a(c(x)))
C(c(x)) → A(c(x))

The TRS R consists of the following rules:

a(x) → x
a(b(x)) → c(x)
b(x) → x
c(c(x)) → b(b(a(a(c(x)))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

C(c(x)) → A(a(c(x)))
A(b(x)) → C(x)
C(c(x)) → A(c(x))

The TRS R consists of the following rules:

a(x) → x
a(b(x)) → c(x)
b(x) → x
c(c(x)) → b(b(a(a(c(x)))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(x)) → C(x)
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(C(x1)) = 0A +
[-I,0A,-I]
·x1

POL(c(x1)) =
/1A\
|-I|
\-I/
 +
/0A-I0A\
|0A1A0A|
\0A1A0A/
·x1

POL(A(x1)) = 0A +
[-I,0A,0A]
·x1

POL(a(x1)) =
/0A\
|-I|
\-I/
 +
/0A0A0A\
|-I0A0A|
\-I0A0A/
·x1

POL(b(x1)) =
/-I\
|0A|
\1A/
 +
/0A0A-I\
|-I0A-I|
\0A1A0A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

c(c(x)) → b(b(a(a(c(x)))))
a(x) → x
a(b(x)) → c(x)
b(x) → x

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

C(c(x)) → A(a(c(x)))
C(c(x)) → A(c(x))

The TRS R consists of the following rules:

a(x) → x
a(b(x)) → c(x)
b(x) → x
c(c(x)) → b(b(a(a(c(x)))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 2 less nodes.

(8) TRUE