NO Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-217.srs

Termination w.r.t. Q of the given QTRS could be disproven:

0 QTRS
↳1 NonTerminationProof (⇒, 776 ms)
↳2 NO

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → x
a(b(x)) → b(b(c(a(x))))
b(x) → x
b(c(c(x))) → a(x)

Q is empty.

(1) NonTerminationProof (COMPLETE transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:
a b b b c b b → a b b b c b b c a

a b b b c b b → a b b b c b b c a
by OverlapClosure OC 2
a b b b c b → a b b b c a
by OverlapClosure OC 2
a b b b c → a b a
by OverlapClosure OC 2
a b b b → a b b c
by OverlapClosure OC 2
a b b → a a
by OverlapClosure OC 3
a b b → b c c a
by OverlapClosure OC 2
a b → b c a
by OverlapClosure OC 3
a b → b b c a
by original rule (OC 1)
b →
by original rule (OC 1)
a b → c a
by OverlapClosure OC 3
a b → b c a
by OverlapClosure OC 3
a b → b b c a
by original rule (OC 1)
b →
by original rule (OC 1)
b →
by original rule (OC 1)
b c c → a
by original rule (OC 1)
a b → b b c
by OverlapClosure OC 2
a b → b b c a
by original rule (OC 1)
a →
by original rule (OC 1)
b c c → a
by original rule (OC 1)
a b → b b c a
by original rule (OC 1)
a b → b b c a
by original rule (OC 1)

(2) NO