YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
|
a(a(x0)) |
→ |
x0 |
|
a(b(b(b(x0)))) |
→ |
b(b(b(a(b(a(x0)))))) |
Proof
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
|
a#(b(b(b(x0)))) |
→ |
a#(x0) |
|
a#(b(b(b(x0)))) |
→ |
a#(b(a(x0))) |
1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1
over the arctic semiring over the integers
| [b(x1)] |
= |
·
x1 +
|
| [a(x1)] |
= |
·
x1 +
|
| [a#(x1)] |
= |
·
x1 +
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
together with the usable
rules
|
a(a(x0)) |
→ |
x0 |
|
a(b(b(b(x0)))) |
→ |
b(b(b(a(b(a(x0)))))) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pair
|
a#(b(b(b(x0)))) |
→ |
a#(b(a(x0))) |
remains.
1.1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1
over the arctic semiring over the integers
| [b(x1)] |
= |
·
x1 +
|
| [a(x1)] |
= |
·
x1 +
|
| [a#(x1)] |
= |
| 0 |
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
·
x1 +
| 0 |
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
together with the usable
rules
|
a(a(x0)) |
→ |
x0 |
|
a(b(b(b(x0)))) |
→ |
b(b(b(a(b(a(x0)))))) |
(w.r.t. the implicit argument filter of the reduction pair),
all pairs could be removed.
1.1.1.1 P is empty
There are no pairs anymore.