YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size12/size-12-alpha-2-num-5.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(a(x)) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(b(a(x)))) → A(a(b(a(b(b(x))))))
A(b(b(a(x)))) → A(b(a(b(b(x)))))
A(b(b(a(x)))) → A(b(b(x)))

The TRS R consists of the following rules:

a(a(x)) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(b(a(x)))) → A(b(a(b(b(x)))))
A(b(b(a(x)))) → A(b(b(x)))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[-I,0A,-I]
·x1

POL(b(x1)) =
/0A\
|-I|
\-I/
+
/0A0A0A\
|-I-I0A|
\-I0A-I/
·x1

POL(a(x1)) =
/0A\
|1A|
\-I/
+
/0A0A0A\
|-I1A0A|
\-I0A-I/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(b(b(a(x)))) → a(a(b(a(b(b(x))))))
a(a(x)) → x

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(b(a(x)))) → A(a(b(a(b(b(x))))))

The TRS R consists of the following rules:

a(a(x)) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(b(a(x)))) → A(a(b(a(b(b(x))))))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[-I,0A,0A]
·x1

POL(b(x1)) =
/0A\
|0A|
\0A/
+
/-I-I0A\
|-I-I0A|
\0A-I-I/
·x1

POL(a(x1)) =
/1A\
|0A|
\-I/
+
/1A0A0A\
|0A0A-I|
\0A0A-I/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(b(b(a(x)))) → a(a(b(a(b(b(x))))))
a(a(x)) → x

(6) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

a(a(x)) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(8) YES