YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
|
a(a(a(b(x0)))) |
→ |
b(a(b(a(a(a(x0)))))) |
|
a(b(x0)) |
→ |
x0 |
Proof
1 String Reversal
Since only unary symbols occur, one can reverse all terms and obtains the TRS
|
b(a(a(a(x0)))) |
→ |
a(a(a(b(a(b(x0)))))) |
|
b(a(x0)) |
→ |
x0 |
1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
|
b#(a(a(a(x0)))) |
→ |
b#(x0) |
|
b#(a(a(a(x0)))) |
→ |
b#(a(b(x0))) |
1.1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over (3 x 3)-matrices with strict dimension 1
over the arctic semiring over the integers
| [a(x1)] |
= |
·
x1 +
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
| 0 |
-∞
|
-∞
|
|
| [b(x1)] |
= |
·
x1 +
|
-∞
|
-∞
|
-∞
|
| 0 |
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
| [b#(x1)] |
= |
·
x1 +
| 0 |
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
-∞
|
-∞
|
-∞
|
|
together with the usable
rules
|
b(a(a(a(x0)))) |
→ |
a(a(a(b(a(b(x0)))))) |
|
b(a(x0)) |
→ |
x0 |
(w.r.t. the implicit argument filter of the reduction pair),
all pairs could be removed.
1.1.1.1 P is empty
There are no pairs anymore.