YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Waldmann_07_size11/size-11-alpha-2-num-2.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(b(a(x)))) → A(a(b(a(b(b(x))))))
A(b(b(a(x)))) → A(b(a(b(b(x)))))
A(b(b(a(x)))) → A(b(b(x)))

The TRS R consists of the following rules:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(b(a(x)))) → A(b(b(x)))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[0A,-I,0A]
·x1

POL(b(x1)) =
/0A\
|-I|
\-I/
+
/-I-I0A\
|-I-I-I|
\-I0A-I/
·x1

POL(a(x1)) =
/0A\
|1A|
\0A/
+
/0A0A-I\
|1A1A-I|
\0A0A0A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(b(a(x)))) → A(a(b(a(b(b(x))))))
A(b(b(a(x)))) → A(b(a(b(b(x)))))

The TRS R consists of the following rules:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(b(a(x)))) → A(b(a(b(b(x)))))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[0A,-I,0A]
·x1

POL(b(x1)) =
/0A\
|0A|
\0A/
+
/-I-I-I\
|0A-I-I|
\-I0A-I/
·x1

POL(a(x1)) =
/1A\
|0A|
\0A/
+
/1A-I1A\
|0A0A0A|
\0A0A0A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(b(a(x)))) → A(a(b(a(b(b(x))))))

The TRS R consists of the following rules:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(b(b(a(x)))) → A(a(b(a(b(b(x))))))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = -I +
[0A,-I,-I]
·x1

POL(b(x1)) =
/0A\
|0A|
\0A/
+
/-I-I0A\
|-I-I-I|
\-I0A-I/
·x1

POL(a(x1)) =
/0A\
|1A|
\-I/
+
/0A0A-I\
|1A1A0A|
\0A0A0A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

(8) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

a(x) → x
a(b(b(a(x)))) → a(a(b(a(b(b(x))))))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(10) YES