YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
b(b(b(a(b(x0))))) |
→ |
b(a(b(b(a(b(x0)))))) |
b(a(b(b(x0)))) |
→ |
b(b(a(b(a(b(x0)))))) |
b(a(b(a(a(b(b(x0))))))) |
→ |
b(a(a(b(a(a(b(b(b(a(b(x0))))))))))) |
Proof
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
b#(b(b(a(b(x0))))) |
→ |
b#(a(b(b(a(b(x0)))))) |
b#(a(b(b(x0)))) |
→ |
b#(a(b(x0))) |
b#(a(b(b(x0)))) |
→ |
b#(a(b(a(b(x0))))) |
b#(a(b(b(x0)))) |
→ |
b#(b(a(b(a(b(x0)))))) |
b#(a(b(a(a(b(b(x0))))))) |
→ |
b#(a(b(x0))) |
b#(a(b(a(a(b(b(x0))))))) |
→ |
b#(b(a(b(x0)))) |
b#(a(b(a(a(b(b(x0))))))) |
→ |
b#(b(b(a(b(x0))))) |
b#(a(b(a(a(b(b(x0))))))) |
→ |
b#(a(a(b(b(b(a(b(x0)))))))) |
b#(a(b(a(a(b(b(x0))))))) |
→ |
b#(a(a(b(a(a(b(b(b(a(b(x0))))))))))) |
1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.