NO Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Secret_06_SRS/multum6-shift.srs

Termination w.r.t. Q of the given QTRS could be disproven:

0 QTRS
↳1 NonTerminationProof (⇒, 3925 ms)
↳2 NO

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

B(x) → W(M(M(M(V(x)))))
M(x) → x
M(V(c(x))) → V(Xc(x))
M(V(b(x))) → V(Xb(x))
M(V(a(x))) → V(Xa(x))
Xc(c(x)) → c(Xc(x))
Xc(b(x)) → b(Xc(x))
Xc(a(x)) → a(Xc(x))
Xb(c(x)) → c(Xb(x))
Xb(b(x)) → b(Xb(x))
Xb(a(x)) → a(Xb(x))
Xa(c(x)) → c(Xa(x))
Xa(b(x)) → b(Xa(x))
Xa(a(x)) → a(Xa(x))
Xc(E(x)) → c(E(x))
Xb(E(x)) → b(E(x))
Xa(E(x)) → a(E(x))
W(V(x)) → R(L(x))
L(c(x)) → Yc(L(x))
L(b(x)) → Yb(L(x))
L(a(x)) → Ya(L(x))
L(c(c(b(x)))) → D(a(c(b(x))))
L(a(c(b(a(x))))) → D(b(c(c(x))))
L(b(a(c(x)))) → D(a(b(c(a(x)))))
L(b(c(a(x)))) → D(c(a(b(x))))
Yc(D(x)) → D(c(x))
Yb(D(x)) → D(b(x))
Ya(D(x)) → D(a(x))
R(D(x)) → B(x)

Q is empty.

(1) NonTerminationProof (COMPLETE transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:
B c a b E → B c a b E

B c a b E → B c a b E
by OverlapClosure OC 3
B c a b E → R D c a b E
by OverlapClosure OC 3
B c a b E → R L b c a E
by OverlapClosure OC 2
B c a b E → R L b c Xa E
by OverlapClosure OC 3
B c a b E → R L b Xa c E
by OverlapClosure OC 2
B c a b → R L b Xa Xc
by OverlapClosure OC 3
B c a b → R L Xa b Xc
by OverlapClosure OC 2
B c a → R L Xa Xc
by OverlapClosure OC 3
B c a → W V Xa Xc
by OverlapClosure OC 3
B c a → W M V a Xc
by OverlapClosure OC 2
B c → W M V Xc
by OverlapClosure OC 2
B → W M M V
by OverlapClosure OC 3
B → W M M M V
by original rule (OC 1)
M →
by original rule (OC 1)
M V c → V Xc
by original rule (OC 1)
Xc a → a Xc
by original rule (OC 1)
M V a → V Xa
by original rule (OC 1)
W V → R L
by original rule (OC 1)
Xc b → b Xc
by original rule (OC 1)
Xa b → b Xa
by original rule (OC 1)
Xc E → c E
by original rule (OC 1)
Xa c → c Xa
by original rule (OC 1)
Xa E → a E
by original rule (OC 1)
L b c a → D c a b
by original rule (OC 1)
R D → B
by original rule (OC 1)

(2) NO