YES Termination w.r.t. Q proof of /home/cern_httpd/provide/research/cycsrs/tpdb/TPDB-d9b80194f163/SRS_Standard/Mixed_SRS/02.srs

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(a(a(a(x)))) → b(a(a(b(x))))
b(a(b(x))) → a(b(a(x)))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(a(a(x)))) → B(a(a(b(x))))
A(a(a(a(x)))) → A(a(b(x)))
A(a(a(a(x)))) → A(b(x))
A(a(a(a(x)))) → B(x)
B(a(b(x))) → A(b(a(x)))
B(a(b(x))) → B(a(x))
B(a(b(x))) → A(x)

The TRS R consists of the following rules:

a(a(a(a(x)))) → b(a(a(b(x))))
b(a(b(x))) → a(b(a(x)))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


A(a(a(a(x)))) → A(a(b(x)))
A(a(a(a(x)))) → A(b(x))
A(a(a(a(x)))) → B(x)
B(a(b(x))) → B(a(x))
B(a(b(x))) → A(x)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(A(x1)) = 1 + x1   
POL(B(x1)) = 1 + x1   
POL(a(x1)) = 1 + x1   
POL(b(x1)) = 1 + x1   

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

b(a(b(x))) → a(b(a(x)))
a(a(a(a(x)))) → b(a(a(b(x))))

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(a(a(x)))) → B(a(a(b(x))))
B(a(b(x))) → A(b(a(x)))

The TRS R consists of the following rules:

a(a(a(a(x)))) → b(a(a(b(x))))
b(a(b(x))) → a(b(a(x)))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04,JAR06].


The following pairs can be oriented strictly and are deleted.


B(a(b(x))) → A(b(a(x)))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]:

POL(A(x1)) = 0A +
[-I,0A,-I]
·x1

POL(a(x1)) =
/0A\
|0A|
\-I/
+
/-I0A0A\
|0A1A1A|
\0A-I-I/
·x1

POL(B(x1)) = -I +
[0A,0A,1A]
·x1

POL(b(x1)) =
/0A\
|0A|
\0A/
+
/1A0A0A\
|-I-I1A|
\0A-I1A/
·x1

The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented:

b(a(b(x))) → a(b(a(x)))
a(a(a(a(x)))) → b(a(a(b(x))))

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(a(a(a(x)))) → B(a(a(b(x))))

The TRS R consists of the following rules:

a(a(a(a(x)))) → b(a(a(b(x))))
b(a(b(x))) → a(b(a(x)))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.

(8) TRUE