YES
0 QTRS
↳1 QTRS Reverse (⇔, 0 ms)
↳2 QTRS
↳3 RFCMatchBoundsTRSProof (⇔, 0 ms)
↳4 YES
0(1(2(3(4(x))))) → 0(2(3(1(4(x)))))
0(5(1(2(3(4(x)))))) → 0(1(2(5(3(4(x))))))
0(5(1(2(3(4(x)))))) → 0(5(2(1(3(4(x))))))
0(5(1(2(3(4(x)))))) → 5(0(2(3(1(4(x))))))
0(5(2(3(1(4(x)))))) → 0(1(5(2(3(4(x))))))
4(3(2(1(0(x))))) → 4(1(3(2(0(x)))))
4(3(2(1(5(0(x)))))) → 4(3(5(2(1(0(x))))))
4(3(2(1(5(0(x)))))) → 4(3(1(2(5(0(x))))))
4(3(2(1(5(0(x)))))) → 4(1(3(2(0(5(x))))))
4(1(3(2(5(0(x)))))) → 4(3(2(5(1(0(x))))))
4(3(2(1(0(x))))) → 4(1(3(2(0(x)))))
4(3(2(1(5(0(x)))))) → 4(3(5(2(1(0(x))))))
4(3(2(1(5(0(x)))))) → 4(3(1(2(5(0(x))))))
4(3(2(1(5(0(x)))))) → 4(1(3(2(0(5(x))))))
4(1(3(2(5(0(x)))))) → 4(3(2(5(1(0(x))))))
The certificate consists of the following enumerated nodes:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21
Node 1 is start node and node 2 is final node.
Those nodes are connected through the following edges: