YES Termination Proof

Termination Proof

by ttt2 (version ttt2 1.15)

Input

The rewrite relation of the following TRS is considered.

0(1(2(x0))) 0(1(3(2(x0))))
0(1(2(x0))) 0(2(1(0(x0))))
0(1(2(x0))) 0(2(1(3(x0))))
0(1(2(x0))) 0(2(2(1(x0))))
0(1(2(x0))) 0(2(2(1(4(x0)))))
0(1(2(x0))) 5(1(0(5(2(3(x0))))))
0(2(4(x0))) 0(2(1(4(3(x0)))))
0(4(2(x0))) 4(0(2(3(x0))))
0(4(2(x0))) 4(0(5(5(2(x0)))))
0(0(4(2(x0)))) 0(0(2(2(3(4(x0))))))
0(1(2(2(x0)))) 0(2(1(0(2(x0)))))
0(1(2(2(x0)))) 1(3(0(2(2(x0)))))
0(1(2(4(x0)))) 0(1(4(2(3(x0)))))
0(1(2(4(x0)))) 4(0(2(2(1(1(x0))))))
0(1(2(4(x0)))) 4(0(5(5(2(1(x0))))))
0(1(2(5(x0)))) 3(5(5(2(1(0(x0))))))
0(1(4(2(x0)))) 0(5(2(1(4(x0)))))
0(1(5(2(x0)))) 1(5(0(2(3(x0)))))
0(1(5(2(x0)))) 0(2(2(1(0(5(x0))))))
0(1(5(2(x0)))) 5(5(0(2(1(3(x0))))))
0(2(4(2(x0)))) 0(5(4(3(2(2(x0))))))
0(3(1(2(x0)))) 0(2(1(3(2(x0)))))
0(3(1(2(x0)))) 1(0(2(5(3(x0)))))
0(3(1(2(x0)))) 1(5(0(2(3(x0)))))
0(3(1(2(x0)))) 3(0(2(2(1(x0)))))
0(3(1(2(x0)))) 3(2(2(1(0(x0)))))
0(3(1(2(x0)))) 0(3(2(3(1(3(x0))))))
0(3(4(2(x0)))) 0(2(2(3(4(x0)))))
5(0(1(2(x0)))) 1(3(2(5(0(x0)))))
5(0(1(2(x0)))) 5(0(2(1(3(3(x0))))))
0(1(1(2(5(x0))))) 5(0(2(5(1(1(x0))))))
0(2(3(4(2(x0))))) 3(2(2(3(4(0(x0))))))
0(3(1(2(5(x0))))) 2(3(1(3(0(5(x0))))))
0(3(1(5(2(x0))))) 0(3(2(5(1(2(x0))))))
0(3(4(1(4(x0))))) 0(5(3(1(4(4(x0))))))
0(3(5(1(2(x0))))) 5(5(3(2(1(0(x0))))))
0(4(0(4(2(x0))))) 4(4(0(0(2(2(x0))))))
0(4(1(1(2(x0))))) 3(1(4(0(2(1(x0))))))
0(4(1(2(2(x0))))) 4(1(0(2(2(3(x0))))))
0(4(1(2(5(x0))))) 3(4(1(0(2(5(x0))))))
0(4(2(1(2(x0))))) 4(1(3(2(0(2(x0))))))
0(4(2(1(4(x0))))) 0(2(1(4(4(4(x0))))))
0(4(2(5(2(x0))))) 5(4(3(2(2(0(x0))))))
0(4(5(1(2(x0))))) 1(4(2(0(5(5(x0))))))
0(4(5(1(2(x0))))) 4(0(2(5(1(1(x0))))))
5(0(1(2(2(x0))))) 5(0(2(2(1(2(x0))))))
5(0(2(4(2(x0))))) 0(2(2(5(1(4(x0))))))
5(0(4(4(2(x0))))) 0(5(2(5(4(4(x0))))))

Proof

1 String Reversal

Since only unary symbols occur, one can reverse all terms and obtains the TRS
2(1(0(x0))) 2(3(1(0(x0))))
2(1(0(x0))) 0(1(2(0(x0))))
2(1(0(x0))) 3(1(2(0(x0))))
2(1(0(x0))) 1(2(2(0(x0))))
2(1(0(x0))) 4(1(2(2(0(x0)))))
2(1(0(x0))) 3(2(5(0(1(5(x0))))))
4(2(0(x0))) 3(4(1(2(0(x0)))))
2(4(0(x0))) 3(2(0(4(x0))))
2(4(0(x0))) 2(5(5(0(4(x0)))))
2(4(0(0(x0)))) 4(3(2(2(0(0(x0))))))
2(2(1(0(x0)))) 2(0(1(2(0(x0)))))
2(2(1(0(x0)))) 2(2(0(3(1(x0)))))
4(2(1(0(x0)))) 3(2(4(1(0(x0)))))
4(2(1(0(x0)))) 1(1(2(2(0(4(x0))))))
4(2(1(0(x0)))) 1(2(5(5(0(4(x0))))))
5(2(1(0(x0)))) 0(1(2(5(5(3(x0))))))
2(4(1(0(x0)))) 4(1(2(5(0(x0)))))
2(5(1(0(x0)))) 3(2(0(5(1(x0)))))
2(5(1(0(x0)))) 5(0(1(2(2(0(x0))))))
2(5(1(0(x0)))) 3(1(2(0(5(5(x0))))))
2(4(2(0(x0)))) 2(2(3(4(5(0(x0))))))
2(1(3(0(x0)))) 2(3(1(2(0(x0)))))
2(1(3(0(x0)))) 3(5(2(0(1(x0)))))
2(1(3(0(x0)))) 3(2(0(5(1(x0)))))
2(1(3(0(x0)))) 1(2(2(0(3(x0)))))
2(1(3(0(x0)))) 0(1(2(2(3(x0)))))
2(1(3(0(x0)))) 3(1(3(2(3(0(x0))))))
2(4(3(0(x0)))) 4(3(2(2(0(x0)))))
2(1(0(5(x0)))) 0(5(2(3(1(x0)))))
2(1(0(5(x0)))) 3(3(1(2(0(5(x0))))))
5(2(1(1(0(x0))))) 1(1(5(2(0(5(x0))))))
2(4(3(2(0(x0))))) 0(4(3(2(2(3(x0))))))
5(2(1(3(0(x0))))) 5(0(3(1(3(2(x0))))))
2(5(1(3(0(x0))))) 2(1(5(2(3(0(x0))))))
4(1(4(3(0(x0))))) 4(4(1(3(5(0(x0))))))
2(1(5(3(0(x0))))) 0(1(2(3(5(5(x0))))))
2(4(0(4(0(x0))))) 2(2(0(0(4(4(x0))))))
2(1(1(4(0(x0))))) 1(2(0(4(1(3(x0))))))
2(2(1(4(0(x0))))) 3(2(2(0(1(4(x0))))))
5(2(1(4(0(x0))))) 5(2(0(1(4(3(x0))))))
2(1(2(4(0(x0))))) 2(0(2(3(1(4(x0))))))
4(1(2(4(0(x0))))) 4(4(4(1(2(0(x0))))))
2(5(2(4(0(x0))))) 0(2(2(3(4(5(x0))))))
2(1(5(4(0(x0))))) 5(5(0(2(4(1(x0))))))
2(1(5(4(0(x0))))) 1(1(5(2(0(4(x0))))))
2(2(1(0(5(x0))))) 2(1(2(2(0(5(x0))))))
2(4(2(0(5(x0))))) 4(1(5(2(2(0(x0))))))
2(4(4(0(5(x0))))) 4(4(5(2(5(0(x0))))))

1.1 Bounds

The given TRS is match-bounded by 1. This is shown by the following automaton.