YES
Termination Proof
Termination Proof
by ttt2 (version ttt2 1.15)
Input
The rewrite relation of the following TRS is considered.
|
0(0(0(0(x0)))) |
→ |
0(1(1(1(x0)))) |
|
1(0(0(1(x0)))) |
→ |
0(0(0(0(x0)))) |
Proof
1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
|
0#(0(0(0(x0)))) |
→ |
1#(x0) |
|
0#(0(0(0(x0)))) |
→ |
1#(1(x0)) |
|
0#(0(0(0(x0)))) |
→ |
1#(1(1(x0))) |
|
0#(0(0(0(x0)))) |
→ |
0#(1(1(1(x0)))) |
|
1#(0(0(1(x0)))) |
→ |
0#(x0) |
|
1#(0(0(1(x0)))) |
→ |
0#(0(x0)) |
|
1#(0(0(1(x0)))) |
→ |
0#(0(0(x0))) |
|
1#(0(0(1(x0)))) |
→ |
0#(0(0(0(x0)))) |
1.1 Reduction Pair Processor with Usable Rules
Using the linear polynomial interpretation over the arctic semiring over the integers
| [1(x1)] |
= |
1 ·
x1 +
-∞
|
| [1#(x1)] |
= |
6 ·
x1 +
-∞
|
| [0(x1)] |
= |
1 ·
x1 +
-∞
|
| [0#(x1)] |
= |
5 ·
x1 +
-∞
|
together with the usable
rules
|
0(0(0(0(x0)))) |
→ |
0(1(1(1(x0)))) |
|
1(0(0(1(x0)))) |
→ |
0(0(0(0(x0)))) |
(w.r.t. the implicit argument filter of the reduction pair),
the
pairs
|
0#(0(0(0(x0)))) |
→ |
1#(1(1(x0))) |
|
0#(0(0(0(x0)))) |
→ |
0#(1(1(1(x0)))) |
remain.
1.1.1 Dependency Graph Processor
The dependency pairs are split into 1
component.